Visual Basic Scripting Edition  

InStrRev Function

Returns the position of an occurrence of one string within another, from the end of string.

InStrRev(string1, string2[, start[, compare]])


Required. String expression being searched.
Required. String expression being searched for.
Optional. Numeric expression that sets the starting position for each search. If omitted, -1 is used, which means that the search begins at the last character position. If start contains Null, an error occurs.
Optional. Numeric value indicating the kind of comparison to use when evaluating substrings. If omitted, a binary comparison is performed. See Settings section for values.


The compare argument can have the following values:

Constant Value Description
vbBinaryCompare 0 Perform a binary comparison.
vbTextCompare 1 Perform a textual comparison.

Return Values

InStrRev returns the following values:

If InStrRev returns
string1 is zero-length 0
string1 is Null Null
string2 is zero-length start
string2 is Null Null
string2 is not found 0
string2 is found within string1 Position at which match is found
start > Len(string2) 0


The following examples use the InStrRev function to search a string:

Dim SearchString, SearchChar, MyPos
SearchString ="XXpXXpXXPXXP"   ' String to search in.
SearchChar = "P"   ' Search for "P".
MyPos = InstrRev(SearchString, SearchChar, 10, 0)   ' A binary comparison starting at position 10. Returns 9.
MyPos = InstrRev(SearchString, SearchChar, -1, 1)   ' A textual comparison starting at the last position. Returns 12.
MyPos = InstrRev(SearchString, SearchChar, 8)   ' Comparison is binary by default (last argument is omitted). Returns 0.
Note   The syntax for the InStrRev function is not the same as the syntax for the InStr function.


Version 2

See Also

InStr Function